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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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smhchre smhchre
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12 years ago
The problem reads:

Solid iron (III) sulfide reacts with gaseous hydrogen chloride to form solid iron (III) chloride and hydrogen sulfide gas.

It says to balance the equation, but I have no idea where to begin. Could someone possibly walk me through this equation so that I have an example to work with for the others that I have to do?
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#1
12 years ago
First write the formulas from the names given.
Iron (III) sulfide = Fe2S3
Hydrogen chloride = HCl
Iron (III) chloride = FeCl3
Hydrogen sulfide = H2S

Now write them in an equation that represents the written statement.
Fe2S3 + HCl Rightwards Arrow FeCl3 + H2S

Then put coefficients in front of each compound so that the left side of the equation is equal to the right side.
Fe2S3 + 6 HCl = 2 FeCl3 + 3 H2S
(for coefficients of 1, don't put anything)
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#2
12 years ago
First, insert all the chemical formulas into equation.
Fe2S3 (Iron sulfide) + HCl (Hydrogen Chloride) ->  FeCl3 (Iron (III) chloride) + H2S (Hydrogen sulfide)
Fe2S3 + HCl ->  FeCl3+ H2S
Next balance the equation. Ensure that there are equal amounts of everything on each side.
Therefore, Fe2S3 + 6 HCl -> 2 FeCl3 + 3 H2S
For compounds which are with the number 1 in front, ignore and do not write any number for the compound
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