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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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Buddy buddy Buddy buddy
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12 years ago
What mass of sodium hydroxide is required to react with 1.50g of aluminum sulfate to produce aluminum hydroxide and sodium sulfate?

Please tell me how to do this question.
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#1
12 years ago
Al2(SO4)3 +6 NaOH = 2 Al(OH)3 + 3 Na2SO4

moles aluminium sulfate = 1.50 g /342.149 g/mol=0.00438

the ratio between aluminium sulfate and sodium hydroxide is 1 : 6

moles NaOH required = 0.00438 x 6 =0.0263

mass NaOH = 0.0263 mol x 40 g/mol=1.05 g
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