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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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bugaian bugaian
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12 years ago
B) If 212.5g of ammonia gas is produced, how many molecules of hydrogen gas must have reacted with nitrogen?

I need full steps...I don't get it...
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#1
12 years ago
N2 + 3H2 Rightwards Arrow 2NH3

number of moles of NH3 = 212.5 / (14.0+3*1.00) = 12.5
from balanced equation, 1 mole of N2 and 3 moles of H2 will produce 2 moles of NH3.

so now the 12.5 moles NH3 is actually formed by:
12.5/2 = 6.25 moles of N2
12.5/2*3 =  18.75 moles of H2
so
number of molecules of H2 =  6.25 * Avogadro's number = 3.76*10^24
number of molecules of N2 =  18.75* Avogadro's number 1.13*10^25
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