High School Physics Question, Can you help me?

The third force is the sum of the first two, but opposite in direction. In other words, the sum of the three will be zero.

Assuming your angles are referenced to 0º at the +x axis.

Take X and Y components of the first two
F1x = 0
F1y = 50
F2x = 44cos60 = 22
F2y = 44sin60 = 38.1

Add the two
Fx = 22
Fy = 88.1
F = ?(22² + 88.1²) = ?(484 + 7762) = 90.8
? = arctan(88.1/22) = 76.0º

reverse the direction by adding 180 degrees
F3 = 90.8 ?256.0º


to be a nice guy, I'll check by adding all 3 up.
F1x = 0
F1y = 50
F2x = 44cos60 = 22
F2y = 44sin60 = 38.1
F3x = 90.8cos256 = ?22.0
F3y = 90.8sin256 = ?88.1

?Fx = 0+22?22 = 0
?Fy = 50+38.1?88.1 = 0


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