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Home Q & A Board Science-Related Homework Help Mathematics
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daTALLsmurf2 daTALLsmurf2
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12 years ago
A certain experiment has three possible outcomes. The outcomes are mutually exclusive and have probabilities p,  p/2,  and  p/4,  respectively. What is the value of p?

A. 1/7  B. 2/7   C.3/7  D. 4/7   E.5/7
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wrote...
#1
12 years ago
p + p/2 + p/4 = 1

=> (4p + 2p + p)/4 = 1

=> 7p = 4

i.e. p = 4/7......so, D.

Slight Smile>
OAK
wrote...
#2
12 years ago
As the outcomes are exclusive, sum of all outcomes is equal to 1
i.e.,
p+p/2+p/4=1
=> 7/4 p =1
=> p= 4/7


Have a nice day.......
wrote...
#3
12 years ago
p + p/2 + p/4 = 1

MULTIPLY BY 4

4p +2p +p = 4

7p = 4

p =  4/7  ANSWER is D)
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