× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
c
5
j
5
a
5
L
5
f
5
j
5
D
4
k
4
y
4
t
4
h
4
l
4
Home Q & A Board Science-Related Homework Help Mathematics
New Topic  
riya3rg riya3rg
wrote...
Posts: 86
Rep: 0 0
11 years ago
Methods of Solving Quadratic Equations:
Apply the square root Property of Equations to find the solution set.

x^2 = 9

{___,____}

(3x-1)^2 = 5

(__+ sqrt ___/__, ___- sqrt__/__)

Help! Thanks!
Read 817 times
5 Replies

Related Topics

Replies
wrote...
#1
11 years ago
take the Square root of both sides
wrote...
#2
11 years ago
x^2 = 9

{_3__,_-3___}

(3x-1)^2 = 5

(_1_+ sqrt _5__/_3_, _1__- sqrt_5_/_3_)
wrote...
#3
11 years ago
first one's root 9, so +/- 3

second one is:
3x-1=root5
x=(root5+1)/3
wrote...
#4
11 years ago
sqrt is an operator just like any other (e.g., +, - , / , X); so keep an equation balanced, you have to use the operator on both sides of the equation.

Thus:

sqrt(x^2) = sqrt(9)
x = +- 3

sqrt(3x - 1)^2 = sqrt(5)
3x - 1 = sqrt(5)
3x = sqrt(5) + 1
x = [sqrt(5) + 1]/3
wrote...
#5
11 years ago
X^2 = 9
X = (3, -3)

(3x-1)^2 = 5
(3x-1)(3x-1) = 5
9x^2 - 3x - 3x +1 = 5
9x^2 - 6x - 4 = 0
6+/-sqrt([-6]^2 - 4 [9][-4])/2(9)
6 +/- sqrt(36 + 144)/18
6 +/- sqrt(180)/18
6 +/- 13.4164/18
19.4164/18 & -7.4164/18
1.0786  &  -0.412022
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  706 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 742
  
 386
  
 2261
Your Opinion
Do you believe in global warming?
Votes: 422
Previous poll results: Which country would you like to visit for its food?