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Ddiv7433 Ddiv7433
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11 years ago
I know that I am taking baby steps through astronomy class but it helps if I do the problem through the week and refer back to how you are doing it and compare answers.  I really appreciate your help more than you will ever know..and you ever have a nursing question I am the one to answer..Thank you and thank you!
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#1
11 years ago
Newton's version of Kepler's third law tells you that d[AU]^3 = P[years]^2 * M[SolarMasses]

In this case: M = d^3/P^2 = 8^3 / 20^2 = 1.28 M_Sun.
wrote...
#2
11 years ago
M+m= A^3/P^2
M+m= 8^3/20^2
M+m= 1.28 Solar Masses
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