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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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rks23456 rks23456
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11 years ago
What is the pH of a solution of a monoprotic acid with a pKa of 7 if it is 33.8 % ionized in solution? Give your answer to two decimal places.
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#1
11 years ago
Use
pH = pKa + log([A-]/[HA])
A- is the acid's anion. If the solution is 33.8% ionized, that's how much is left in solution of the anion.
HA is what is left of the acid in solution as unionized.

pH = 7 + log[33.8/66.2]

pH = 7 + (-0.2919)
pH = 6.71
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