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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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_brooksd _brooksd
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11 years ago
The answer is 0.999 but I don't know why. can someone explain all the steps? Mostly how to find the concentrations to use in the formula pH = pKa + log(/[HB]), assuming that is how you solve it.
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#1
11 years ago
[H+] = [A-] = 10^-3 M
[HA] = 0.100 - 10^-3 =0.099 M

Ka = ( 10^-3)^2 / 0.099 = 1.0 x 10^-5
pKa = 4.999
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