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madiward madiward
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8 years ago
The specific heat of copper is 0.385 J/(g ⋅ °C). If 34.2 g of copper, initially at 21.0°C, absorbs 4.689 kJ, what will be the final temperature of the copper?
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wrote...
Educator
8 years ago
Heat absorbed = (mass Cu)(sp. ht. Cu)(Tf - Ti)
4689 J = (34.2 g)(0.385 J / g C)(Tf - 24.0 C)
4689 = 13.2Tf - 316
5005 = 13.2Tf
Tf = 379 C
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