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Home Q & A Board Science-Related Homework Help Physics
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rjcool123 rjcool123
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11 years ago
The current is given by the complex number I=9<21 degrees amperes.
Calculate the angle between V and I

The power given P=(V)(I)cosx watts, where V and I are magnitudes and x is the angle between V and I

Can some one help me with this question!! Please.......
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#1
11 years ago
V = ?(5² + 12²)
  I = 9 <21 deg.

 x = <67.38 - <21 = 46.38 deg.

 P = VI cosx = 13*9 cos(46.38) = (117)0.68987 = 80.7 W
wrote...
#2
11 years ago
V = ?(5^2 + 12^2) at an angle of inverse tan (12/5)
the ?169 = 13 and the inverse tan of 2.5 = 67.38°
V = 5 + j12 = 13 < 67.38° volts
I = 9 < 21°  amperes
the angle is 46.38°
P = 13*9 cos 46.38°
1P = 117 cos 46.38° = 80.71 watts   since the cos 46.38° = 0.6899

answer  P = 80.71 watts
Julie Appleton
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