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Home Q & A Board Science-Related Homework Help Physics
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RJW RJW
wrote...
11 years ago
For the following lighting circuit each lamp has a resistance of 12 ohms and the battery voltage is 13. 8 Volts
There is a simple circuit of a battery, fuse and 3 lamps which are in a parallel circuit, how would I calculate the current, voltage and resistance?  
Thank you for taking your time to answer what seems to me being a very difficult question.
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wrote...
#1
11 years ago
you said the voltage is 13.8, so we have to believe you
the current through any of the three lamps is 13.8/12 amps
the total current is 3(13.8/12) = 13.8/4 amps
the equivalent resistance is then 4 ohms
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