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Home Q & A Board Biology-Related Homework Help Genetics and Developmental Biology
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rkoch rkoch
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11 years ago
In a cross: female Aa Bb cc Dd x male Aa bb Cc Dd, what proportion of progeny will be
phenotypically identical to the female parent? (Assume independent assortment of all genes and
simple dominance of allele shown in capitals
The answer is 9/64.
but i keep getting 9/128
1/2(female)x
3/4(A/?)x
1/2(B/b)x
1/2(cc)x
3/4(D/?)
please tell me what im doing wrong!
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wrote...
#1
11 years ago
it will be 1/2 x 1/2 x 1/2 x 1/2 = 1/16 chance

cross each genotype one at a time and find the probablilty the cross would be the same as the mother and then multiply them all together, if that makes sense.
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