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tommyt_ tommyt_
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11 years ago
15.50 mL of a 0.1075 M NaOH solution are required to neutralize 15.00 mL of a sulfuric acid solution.  How many moles of NaOH were added to the reaction flask?
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wrote...
11 years ago
0.1075 moles/L times 0.1550 L is 0.0166625 moles of NaOH  or 1.67 X 10 ^ (-2) moles
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