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asim14990 asim14990
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12 years ago
A 1-L flask is filled with 1.00 g of argon at 25C . A sample of ethane vapor is added to the same flask until the total pressure is 1.10atm .

What is the partial pressure of ethane in the flask?
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wrote...
12 years ago
Ptotal = Pargon + Pethane

PV = nRT
P = nRT/V
Pargon = (1.00g x 1mole/39.95g) x (0.08206 Latm/moleK) x (298.15K) / (1L) = 0.61atm

Pethane = 1.10atm - 0.61atm = 0.49atm
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