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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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rknicker rknicker
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Posts: 103
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11 years ago
1.)  HIO(subscript 2)       What is the oxidation number of "i"?

2.)  Cr2O7 -2                  What is the oxidation number of "Cr"?
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wrote...
#1
11 years ago
HIO2

H = +1
2 x O = 2 x -2 = -4
I = ?
==============
Total = 0 since HIO2 is neutral. So +1 + (-4) + I = 0; I = +3


Cr2O7 2-

2 x Cr = ?
7 x O = 7 x -2 = -14
===============
Total = -2 (the charge on Cr2O7 2-); 2 Cr - 14 = -2; 2 Cr = +12; Cr = +6
wrote...
#2
11 years ago
H=+ O=-2 therefore I=3 as (1+3-2=2)
same procedure for the second one.
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