I need the steps on how to do Mass to Mass Stoichiometry?

First calculate the molecular weight of LiOH from the atomic weights tables
Li = 6.94
O = 15.999
H = 1.008
add the above: molecular weight of LiOH is 23.95 g/mol.

Then calculate the moles of LiOH:
(10 g) / (23.95 g/mol) = 0.418 mol LiOH

You see from the equation that 1 mol LiOH is converted to 1 mol LiBr, so 0.418 mol LiOH is converted to 0.418 mol LiBr.

Finally, convert 0.418 mol LiBr into grams.
The molecular weight of LiBr = 6.94 + 79.904 = 86.84 g/mol.
So (0.418 mol)(86.84 g/mol) = 36.3 g LiBr

Note: if you're unsure whether to multiply or divide, look at the units.  You want them to cancel.