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micooo micooo
wrote...
Posts: 56
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11 years ago
120 mL at 28 C
and
150 mL at 107 C

Does anyone know how to calculate this without using a graph???
(I know what absolute zero but how do you CALCULATE it using these values??)
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wrote...
11 years ago
absoloute zero is -273 C.
wrote...
11 years ago
Volume and temperature are related to the absolute temperature.  We can define it in terms of C.

AT=x+T

AT=absolute temp
T=temperature


120/(x+28)=150/(x+107)

Solve for x
wrote...
11 years ago
Look at the ratio of the change in volume to the change in temperature.

DV/DT = (150-120) / (107-28) = 0.3797

Now, set up a second ratio between either point and a volume of zero and a new T

DV/DT = (150-0) / ( 107 - T) = 0.3797
Solve for T
T = -288 C

DV/DT = (120-0) / (28 - T) = 0.3797
Solve for T
T = -288C

According to your data, absolute zero, the point where the volume of the gas is zero, is -288C.

In essence you are doing the same thing as you would with a graph of V vs T.  DV/DT is the slope of a line through your two data points, and we are solving for T when V is zero.

wrote...
11 years ago
But i think at absolute 0 only pressuer goes to 0 and not volume. hence i think ur calculation is wrong
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