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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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juicylucy juicylucy
wrote...
11 years ago
SO2 reacts with H2S as follows:
2H2S+SO2--->3S+2H2O

When 7.50g of H2S reacts with 12.75g of SO2, which is the limiting reagent?
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wrote...
#1
11 years ago
7.50g of H2S is   n= 7.5 / 34.081 = 0.22 moles
12.75g of SO2 is n= 12.75 / 64.064 = 0.2 moles
the balanced equation shows that we need 2 moles of hydrogen sulfide pr mole sulfur dioxide, thus making H2S the limiting reagent (this runs out before SO2). When all the H2S has reacted, there is still 0.09 moles of SO2 left
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