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micphy micphy
wrote...
Posts: 95
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11 years ago
Pectinose, a simple sugar, has an empirical formula of CH2O and a molar mass of 150 g/mol. What is its molecular formula?

How do I solve this?
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wrote...
11 years ago
First find out the weight of the empirical unit. CH2O weighs 30g/mol.
An empirical formula is the most simplified representation of a molecule. So if you divide the molecular weight by the empirical formula weight, you will get the number of empirical units. i.e. 5. The molecular formula will be C5H10O5
wrote...
11 years ago
The Molecular formula is just the empirical formula multiplied by a constant.  To solve this question we need to Find Molar Mass of the Empirical Formula.

Molecular Mass of CH20 = 30g/mol

150g/mol / 30g/mol = 5

So lets multiply the Empirical Formula by 5

5(CH2O) = C5H10O5

The answer if C5H10O5
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