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tommy_gun tommy_gun
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11 years ago
A student performing an experiment titrates 1.390 g of KHP with an NaOH solution of unknown concentration. The initial buret reading is 0.73 mL and the final buret reading is 22.38 mL. What is the molarity of the NaOH solution?

Please help with easy and clear calculations.
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micooomicooo
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11 years ago
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11 years ago
They react 1:1
M.Wt KHP= 204.22  so 1.39g=1.39/204.22=0.006806moles
0.006806 moles/21.65ml is sames as=0.006806x1000/21.65 = 0.3144  M per litre
simply:
[NaOH] = 1000 x wt / titre x 204.22
              = 1390 / (22.38-.73 ) x 204.22
               = 0.3144 M
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