what happens to an electron in chlorophyll in photosystem II when the electron absorbs light energy?

1)Photo II absorbs light and energy which causes the P680 molecule to excite its e- and pass it onto an enzyme called plastoquinone.

2) This creates an e- deficiency in Photo II. This deficiency if filled by a molecule called Z protein, a molecule containing Mn. This enzyme is somehow stimulated by the loss of e- in photo II to split two molecules of water. The e- from this reaction are then released to the waiting e- hungry Photosystem II. This step also releases H+ in to the thylakoid space helping to create a proton gradient. O2 is also released in this step.

3)The e- ejected from Photo II are accepted by a molecule called pheophyton.

4) Pheophyton is then reduced(has its e- taken by) plastoquinone which has a higher affinity for e- than Pheophyton.

5) Plastoquinone passes the e- to a cytochrome complex called b6-f complex which has a higher affinity for e- the plastoquinone. This complex passes protons from the stroma into the thylakoid space increasing the proton gradient even more.

Plastoquinone is found within the membrane - it has a long hydrophobic tail.
6) The e- is then passed to plastocyanin which then transfers the e- to an e- deficient Photo I.