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dreamingtruth dreamingtruth
wrote...
Posts: 77
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11 years ago
Boyle’s Law
Calculate the following volumes.  If no ending pressure is given, assume standard pressure.

4) 45.3 L of hydrogen sulfide gas at 90.5 kPa

5) 455 ml of methane, CH4 at 45.2 kPa

6) The capacity of a scuba tank is 80 cubic feet at standard pressure.  If a diver descends to a depth of 100 feet the pressure is quadrupled.  What is the volume in the tank?

7) If a gas occupies 45.8 liters at 95 kPa, what will the pressure be when the volume is 65.3 L?


8) A gas takes up 43.8 L at 103.7 kPa.  What is the volume of the gas at standard pressure?  If 1 mole of a gas = 22.4 liters, How many mole of the gas are present.

If you could help me out, that'd be greatly appreciated
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Replies
wrote...
11 years ago
Hi this is the answer for 4
p1v1=p2v2

v2=p1vi/p2

v2=90.5x45.3/101.3

v2=40.47 litres

is you want me to solve other questions let me know
 
dreamingtruth Author
wrote...
11 years ago
Thank you so much, that really helped. I don't need examples for the others (:
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