Gene of Interest Table

The results depend on whether lactose is present or not.

So I have put + & - in the order: b-gal (no lactose), b-gal(lactose present), permease (no lactose), permease (lactose)

In terms of which enzymes are produced and active:

1. i+P+O+Z+Y+ = - + - +
2. i+P+O+Z-Y+ = - - - +
3. i+P+O+Z+Y- = - - + -
4. i-P+O+Z+Y+ = + + + + (operon never repressed - no repressors)
5. i+P+OcZ+Y+ = + + + + (operator constituatively active)
6. i+P+OcZ+Y+ = + + + + (operator constituatively active)
7. I+P-O+Z+Y- = - - - - (RNA polymerase unable to bind to promotor)
8. i+P+OcZ+Y- / I-P+O+Z-Y+ = + + - + (functional b-gal always produced)
9. I-P+OcZ+Y- / i+P+O+Z-Y+ = + + - +
10. i+P+O+Z+Y- / I-P+OcZ-Y+ = - + + + (functional permease always produced)

Thank you so much! Any way you could explain how you got those?

I don't know how you got those answers but they are all wrong 

Post Merge: 11 years ago

1. i+P+O+Z+Y+ =  ++--
2. i+P+O+Z-Y+ = -+--
3. i+P+O+Z+Y- = +---
4. i-P+O+Z+Y+ = + + + + (operon never repressed - no repressors)
5. i+P+OcZ+Y+ = + + + + (operator constituatively active)
6. i+P+OcZ+Y+ =  +-+-(operator constituatively active)
7. I+P-O+Z+Y- = - - - - (RNA polymerase unable to bind to promotor)
8. i+P+OcZ+Y- / I-P+O+Z-Y+ = +++-(functional b-gal always produced)
9. I-P+OcZ+Y- / i+P+O+Z-Y+ =+++-
10. i+P+O+Z+Y- / I-P+OcZ-Y+ = ++-+ (functional permease always produced)

These are the correct answers..

Great.. I would send that in before knowing they were all wrong!

Just want to confirm Ela posted the correct answers, I did this problem and got the exact same answers.

Yes, Ela was right.