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Home Q & A Board Science-Related Homework Help Mathematics
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firetruckboom firetruckboom
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11 years ago
solve the differential equation y'=(2y+1)/(x+1), with condition y(0)=1.
Please help! This was a test question and I just don't know how to solve it, especially with the linear equation method. Thanks
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#1
11 years ago
y=(2y+1)/(y+1)
y=(2y+1)*(y+1)^(-1)
y'=2(y+1)^(-1)+(-1)(y+1)^(-2)
y'=2(y+1)^(-1)-(y+1)^(-2)
y'=(y+1)^(-2)(2y+1-1)
y'=(y+1)^(-2)(2y)
y'=(2y)(y+1)^(-2)
y'|(0)=0
Answer accepted by topic starter
dave67tapoutdave67tapout
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#2
Posts: 61
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11 years ago
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