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ishtar ishtar
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7 years ago Edited: 7 years ago, ishtar
A planet with the same mass as Earth orbiting at a distance of 1 AU from a star with thirty six times the Sun's mass.

Months for orbit? : Answer required in months.
Post Merge: 7 years ago

Also, I'd like the way to find the answer and not just the solution please and thank you!

I already got this part:
A planet with thrice Earth's mass orbiting at a distance of 1 AU from a star with the same mass as the Sun.: Answer 1 year.
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#1
Educator
7 years ago
1 AU = 1.5 *10^11 m

apply Keplers third law as T^2 =   4pi^2 R^3/GM

here R = 1AU = 1.5 e 11 m

M = 36*1.99 e 30 = 71.64 e30 kgs

so T^2 = (4*3.14*3.14* 1.5e11*1.5e11*1.5e11)/(6.67e-11*71.64 e30)

T^2 = 27.8*10^12

T = 5.272 *10^6 secs

T =5.272e6 /(60*60) = 1464.60 mins

T = 1464.60/24 = 61.025 days

T = 2.03 months
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