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ilikebigbutts ilikebigbutts
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11 years ago
If the coefficient of static friction between the tires and pavement is 0.73, calculate the minimum torque that must be applied to the 50.0 cm diameter wheels of a 1250 kg car in order to "burn rubber" (make the wheels spin, slipping as the car accelerates). Assume that each wheel supports an equal share of the car's weight).
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011jos011jos
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11 years ago
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wrote...
11 years ago
(1250 x 9.8) = 12,250N. weight.
(12,250 x 0.75) = 9,187.5N. minimum force before tyres skid. Divide by 4 = 2,296.8N. force applied by each tyre.
Wheel radius = (50/2) = 25cm., = 0.25 metre.
(2,296.8 x 0.25) = 574.2N/m. torque to each wheel.
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