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Rjune1 Rjune1
wrote...
Posts: 52
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11 years ago
A stone is thrown vertically upwards with an initial speed of vo. At times t and t+2.00s, it has a speed of 0.400 vo. Calculate t. (A:1.50s).

I keep trying to solve for t using the equation v = vo + at, but I get the incorrect answer. What am I doing incorrect?
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LeoLeo
wrote...
Posts: 22
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11 years ago
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when a stone is having a same speed but different time, it means that it is at the same height (let's say h)
the stone needed 2 second from h Rightwards Arrow maximum height Rightwards Arrow h
so the time needed to reach maximum height is 1 second (calculated from distance h.

velocity at maximum height is 0, hence

vf = vi - gt
0 = 0.4xV0 - 10x1
v0 = 25 m/s

now calculate the time t
vf = vi -gt
0.4 V0 = V0 -g.t
10t = 0.6.v0
10t = 0.6 x 25
t = 1.5 s

hope that help ;p
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