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tomochita tomochita
wrote...
Posts: 84
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11 years ago
Two projectiles are launched from the same point at the same angle above the horizontal. Projectile 1 reaches a maximum height twice that of projectile 2.
I got 1.41 but I don't know how to explain this and why?
I got the answer which is 1.41 but I don't know how I got that and I don't know how to explain it.

Thank you
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wrote...
11 years ago
The acceleration along y-axis is constant (because the gravitational force is approximately constant).
Thus, you can use equations for uniformly accelerated motion.
For uniformly accelerated motion, the relationship between velocity and distance travelled is :

v2=v02-2a*s

In our concrete problem, we can write:

vy2=v0y2-2g*h

When the body reaches the maximal height its y-component of velocity is zero, so:

hmax=v0y2/2g

If we use the last equation for both of our bodies:

hmax1/hmax2=(v0y12/2g)/(v0y22/2g)

Thus:

2=(v0y1/v0y2)2

Finally:

Sqrt(2)=(v0y1/v0y2)

Or:

1.41=(v0y1/v0y2)
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