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datdude666 datdude666
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Posts: 75
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11 years ago
A block oscillating on a spring has a maximum kinetic energy of 2.0 J. What will be the maximum kinetic energy if the amplitude is doubled? Explain please!
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NVstudentNVstudent
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11 years ago
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wrote...
11 years ago
Kinetic energy is proportional to the velocity. So

Original KE = (1/2) m v^2
v = x / t
Original KE = (1/2) m (x/t)^2
where x = amplitude.

If x increases to 2x then
New KE = (1/2) m (2x/t)^2 = 4 * (1/2 m x^2/t^2) = 4 * (1/2) m v^2

The new KE is 4 times to original KE. So
new KE = 4 * 2 = 8 J
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