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Home Q & A Board Science-Related Homework Help Physics
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smokeypal23 smokeypal23
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11 years ago
A projectile is launched with an initial speed of 40 m/s at an angle of 30° above the horizontal on flat ground. Neglect air friction.
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#1
11 years ago
At its highest point Vy = 0 and Vx = Ux = U cos(theta) = 40*cos(radians(30)) = 34.64101615 = 34.6 mps.

So V = sqrt(Vx^2 + Vy^2) = Vx = Ux = 34.6 mps.  ANS.
wrote...
#2
11 years ago
Given:
? = 30 Degrees
Vi = 40 m/s
Vix = 34.6 m/s
Viy = 20 m/s

Find:
V@ ?Ymax

Equations:    

?t = (Vf - Vi)/(a)

?y = Vi?t + 1/2a(?t)^2


Solution:

?t = (Vf - Vi)/(a)
?t = (0-20)/(-9.8)
?t = 2.04

?y = Vi?t + 1/2a(?t)^2
?y = (20)(2.04) + 1/2(9.8)(2.04)^2
?y = 61.2 m

If the projectile has no velocity in the y-direction then its velocity is just simply the x-velocity but just incase you were wondering the math behind it is above Slight Smile
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