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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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dawnskie dawnskie
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11 years ago
An oxide of the element X has 84% of X in mass. What is the empirical formula of this oxide?

I have the answer but I don't understand all the steps you take to solve this. If anyone could explain in detail it'd be great...
An oxide of the element X has 84% of X in mass. What is the empirical formula of this oxide?

X = 112u, O = 16u.

I have the answer but I don't understand all the steps you take to solve this. If anyone could explain in detail it'd be great...
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dax
wrote...
#1
11 years ago
Moles X = 84 g / 112 = 0.75
moles O = 100 - 84 / 16 = 1

X 0.75 O

divide by the smallest number

0.75/ 0.75 = 1 => X
1 / 0.75 =1.33 => O

X O 1.33

to get whole numbers multiply by 3

X3O4 is the formula
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