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Home Q & A Board Science-Related Homework Help Physics
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rk rk
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11 years ago
An object moving with constant acceleration has velocity v = 21.9 m/s when it is at x = 6.5 m and v = 35.5 m/s when it is at x = 13.3 m. What is its acceleration?
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wrote...
#1
11 years ago
(Vf)² = (Vi)² + 2×a×d
where
Vf = final velocity = 35.5 m/s
Vi = initial velocity = 21.9
a = acceleration = ?
d = distance = 13.3 m - 6.5 m = 6.8 m
so
35.5² = 21.9² + 2×a×6.8
a = (35.5² - 21.9²) / (2 × 6.8)
a = 57.4 m/s²
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