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Mickie515 Mickie515
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11 years ago
suppose an object has an initial velocity of 15m/s, at an angle of 30 degrees from the x-axis.  what is the maximum height the object will go?
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wrote...
11 years ago
It's all in the vertical velocity component Vv = v0sin(theta).
From h = gt^2/2 you get h = Vv^2/(2g).
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