× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
5
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
Home Q & A Board Science-Related Homework Help Physics
New Topic  
Datnigerian Datnigerian
wrote...
Posts: 80
Rep: 0 0
11 years ago
What is the velocity and acceleration of a free falling object after three meters and six meters? Go to the link provided for virtual lab: http://jersey.uoregon.edu/AverageVelocity/index.html  Please provide formulas and guidance to help me better understand.
Read 406 times
1 Reply

Related Topics

Replies
wrote...
#1
11 years ago
The acceleration of an object near the surface of Earth is a constant called 'g', which equals 9.8 m/s^2.  So this is the acceleration of the object in all cases.

The velocity of the object is given by the equation v  = squareroot(v0^2 + 2*g*h), where v is the velocity, v0 is the initial velocity (0 m/s in this case), and h is the distance fallen.  Simply plug in numbers to find the velocity at various distances.

v at 3m = sqrt(2 * 9.8m/s^2 * 3m) = 7.67 m/s
v at 6m = sqrt(2 * 9.8m/s^2 * 6m) = 10.84 m/s
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  1341 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 386
  
 843
  
 4261