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wrote...
12 years ago
In a 1.35 T magnetic field directed vertically upward, a particle having a charge of magnitude 8.30 uC and initially moving northward at 4.78 km/s  is deflected toward the east.

A)What is the sign of the charge of this particle?
 
The charge is negative.
 The charge is positive.

B) Find the magnetic force on the particle.
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wrote...
12 years ago
Positive.
wrote...
12 years ago
the force is qv x B where v and B are vectors
pointing your right hand north, curling your fingers up, thumb points east  along vxB
so q is positive.  F=qvB
wrote...
12 years ago
__________________

Direction is found by using Flemmings Left Hand rule

First (index) finger vertically up in the direction of field,central finger towards east (direction of motion of charge), then thumb points east for force  on positive charge

 A) The charge is positive.

B) The magnetic force on the particle is 5.3559*10^(-2) N
_____________________________ ______________
wrote...
12 years ago
Flemmings Left Hand Rule??!?!  Is that what they teach in engineering?

You use the Lorentz Right Hand Rule.  Ironically, it's equivelant.  Since the Force is a cross product, -q(B x v) = q (v X B) = Force.  So point the fingers of your right hand in the direction of the charge's motion, then curl your fingers into the direction of the magnetic field.  your thumb points in the direction of the force.  If you use your left hand with this rule, it is backwards, but if you use your left hand and reverse the order its the same (ie, correct).

And yes, I got positive charge as well.
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