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Home Q & A Board Science-Related Homework Help Mathematics
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smluke2000 smluke2000
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11 years ago
Elisabeth is 6 years older than her sister Elisa.  Their mother's age is twice the sum of their ages.  How old are they if their mother is 40.
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wrote...
#1
11 years ago
13 and 7
40 /2 = 20
elizibeth 13
elisa 7
13-7=6
13+7+20

Elisabeth 13
Elisa 7
wrote...
#2
11 years ago
elisabeth is 14 and elisa is 6?
wrote...
#3
11 years ago
that's for me to know ... and you to find out.
wrote...
#4
11 years ago
7 and 13
wrote...
#5
11 years ago
elizabeth-14, elisa- 6

40 divided by 2.
20 minus 6.
wrote...
#6
11 years ago
elisabeth would be 13 and elisa would be 7
wrote...
#7
11 years ago
let x = Elisa's age
x+6 = Elisabeth's age

2(x + x + 6) = 40

solve for x:
2x + 6 = 20
2x = 14
x = 7

They are 7 and 13 years of age.

that's it! Wink Face
wrote...
#8
11 years ago
Ezisabeth is 13, and Elisa is 7

13-7 = 6
13 + 7 = 20
20 * 2 = 40
wrote...
#9
11 years ago
elisabeth = 6 + elisa
40 = 2(elisabeth + elisa)
20 = elisabeth + elisa
elisabeth = (20 - elisa)

20 - elisa = 6 + elisa
-2elisa = -14
elisa = 7
elisabeth = 13
wrote...
#10
11 years ago
Elisa is 14
Elisabeth is 20
wrote...
#11
11 years ago
Elisabeth is 13 and her sis is 7
wrote...
#12
11 years ago
elisabeth x+6, elisa x their sum is 20, 2x+6=20, simplify 2x=14, x=7, other girl is 13.
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#13
11 years ago
half of 40 is 20 and then it would be 2x+6=20 then solve and get 7 and 13
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