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Home Q & A Board Science-Related Homework Help Physics
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smokeyjou smokeyjou
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11 years ago
A space station in the form of a large wheel, 77.2m in diameter, rotates to provide "artificial gravity" of 5.1m/s^2 for the people located on the outer rim of the station.
What is the frequency of the rotational movement for the wheel to produce this effect in units of rev/min?
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#1
11 years ago
The artificial gravity is the centripetal acceleration = r*omega^2

So a = 5.1m/s^2 = 77.2/2m*omega^2 ...Therefore omega= sqrt(2*5.1/77.2) = 0.363rad/s

Converting to correct unit  0.363rad/s*1 rev/2pi rad*60s/min = 3.47rev/min
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