× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
5
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
Home Q & A Board Science-Related Homework Help Physics
New Topic  
smokeyjou smokeyjou
wrote...
Posts: 82
Rep: 1 0
11 years ago
A space station in the form of a large wheel, 77.2m in diameter, rotates to provide "artificial gravity" of 5.1m/s^2 for the people located on the outer rim of the station.
What is the frequency of the rotational movement for the wheel to produce this effect in units of rev/min?
Read 316 times
1 Reply

Related Topics

Replies
wrote...
#1
11 years ago
The artificial gravity is the centripetal acceleration = r*omega^2

So a = 5.1m/s^2 = 77.2/2m*omega^2 ...Therefore omega= sqrt(2*5.1/77.2) = 0.363rad/s

Converting to correct unit  0.363rad/s*1 rev/2pi rad*60s/min = 3.47rev/min
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  1347 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 596
  
 306
  
 369
Your Opinion
Which country would you like to visit for its food?
Votes: 204
Previous poll results: What's your favorite funny biology word?