Top Posters
Since Sunday
f
3
b
2
e
2
b
2
j
2
E
2
o
2
L
2
m
2
R
2
C
2
b
2
New Topic  
illofigas illofigas
wrote...
Posts: 29
Rep: 0 0
11 years ago
So we're doing acid-base titrations and trying to find an unknown concentration of HCl. We used 10 mL of HCl, and titrated with 0.1 M NaOH and used 11.81 mL NaOH. How do I find the concentration of HCl?
Thanks!
Read 271 times
2 Replies
Replies
Answer accepted by topic starter
ritajoshiritajoshi
wrote...
Posts: 5
Rep: 0 0
11 years ago
Sign in or Sign up in seconds to unlock everything for free
This verified answer contains over 130 words.
1

Related Topics

wrote...
11 years ago
Since both have equivalent weights of one, just use the equation M1V1 = M2V2
Thus 10 ml* M HCl = 11.81 ml*0.1 M
or M HCl = 11.81*0.1/10 = 0.1181 M HCl

This is because one mole of OH- will react with one mole of H+ to give water.
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  641 People Browsing
Related Images
  
 207
  
 393
  
 345