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lengjacinto lengjacinto
wrote...
Posts: 52
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11 years ago
a. What as the velocity and speed of the ball after 2 seconds?
b. what was its displacement in the second second?
c. How long did it take the ball to reach its maximum heights?
d. How far was the maximum height from the stationary position?
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wrote...
11 years ago
You first have to convert the units to something uniform. Since you are using English units, the acceleration due to gravity is approximately 32 ft/s^2

Convert velocity to ft/s: V = (3450 in/s)(1 ft/12 in) = 287.5 ft/s

a)
V = Vo + at
V = 287.5 ft/s + (-32 ft/s^2)(2 s)
V = 223.5 ft/s

b)
Displacement:
Y = Yo + Voy t + (1/2)at^2
Y = 0 + (287.5)(2) + (1/2)(-32)(2)^2
Y = 511 ft

c)
Maximum height when V = 0
V = Vo + at
0 = (287.5 ft/s) + (-32)t
t = 8.98 seconds

d)
Maximum height:
Y = Yo + Vo t + (1/2)at^2
Y = 0 + (287.5)(8.98) + (1/2)(-32)(8.98)^2
Y = 1291.5 ft
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