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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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shellysearle shellysearle
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7 years ago


Considering the limiting reactant concept, how many moles of copper(I) sulfide are produced from the reaction of 0.500 mol of copper and 0.750 mol of sulfur?

            2 Cu(s) + S(s) rightwards arrow Cu2S(s)
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7 years ago
The balanced equation for the reaction is:

2Cu + S Rightwards Arrow Cu2S

2 mol Cu reacts with 1 mol S to make 1 mol Cu2S

First, find the limiting reagent. Assume all the Cu is used up.

3 mol Cu x (1 mol S / 2 mol Cu ) = 1.5 mol S required.

Since there is only 1 mol S and 1.5 mol S is required to use up all the Cu, S is the limiting reagent.

Use S to calculate the amount of product formed.

1 mol S x (1 mol Cu2S / 1 mol S) = 1 mol Cu2S
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