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riyadamin riyadamin
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11 years ago
Based on the balanced equation

4H3PO4 + Ca3(PO4)2 ? 3Ca(H2PO4)2

calculate the number of Ca(H2PO4)2 formula units formed when 416 H3PO4 molecules and 96 Ca3(PO4)2 formula units react?
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wrote...
11 years ago
416 molecules of H3PO4 would react completely with 416 x (1/4) = 104 molecules of Ca3(PO4)2, but there is not that much Ca3(PO4)2 present, so Ca3(PO4)2 is the limiting reactant.

96 molecules of Ca3(PO4)2 react to form 96 x (3/1) =
288 molecules of Ca(H2PO4)2
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