× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
5
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
New Topic  
tony51092 tony51092
wrote...
Posts: 65
Rep: 0 0
11 years ago
A phosphoric acid (H3PO4) is titrated with a 0.1214M NaOH Standard Solution. 41.56mL of the Standard is required to reach the end point. The titration reaction is:

H3PO4 (aq) + 3OH^- (aq) -> PO4 ^3- (aq) + 3H2O

What is the mass of the Phosphoric Acid in the solution?

I'd appreciate it if someone could show me how to do this in steps. I'm completely confused and chemistry is not my strong subject.
Read 287 times
1 Reply

Related Topics

Replies
wrote...
#1
11 years ago
Equation:
H3PO4 + 3NaOH ? Na3PO4 + 3H2O
From the equation you will know that 1 mol H3PO4 reacts with 3 mol NaOH
Mol NaOH in 41.56mL of 0.1214M solution = 41.56/1000*0.1214 = 0.005045 mol NaOH
This will react with 0.005045/3 = 0.00168 mol H3PO4

Molar mass H3PO4 = 98g/mol
0.00168 mol = 0.00168*98 = 0.165g H3PO4 Answer.
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  1276 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 408
  
 158
  
 311
Your Opinion
Which of the following is the best resource to supplement your studies:
Votes: 292
Previous poll results: Does a gender wage gap exist in America?