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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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smooth15 smooth15
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11 years ago
The balanced equation is 3BaCl2 + 2Na3PO4 Rightwards Arrow 6NaCl + Ba3(PO4)2. I really need some help, thanks in advance!
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#1
11 years ago
Since the molar mass of sodium phosphate is 3(23) + 94.97 + 4(16) = 227.97 g/mol, we see that require:
(37.6 g Na3PO4) * (1 mol Na3PO4)/(227.97 g Na3PO4) = 0.027 mol Na3PO4.

From the balanced equation, we need:
(0.027 mol Na3PO4) * (3 mol BaCl2)/(2 mol Na3PO4) = 0.0405 mol BaCl2.

Then, since the molar mass of barium chloride is 13.734 + 2(35.45) = 84.63 g/mol, we require:
(0.0405 mol BaCl2) * (84.63 g BaCl2)/(1 mol BaCl2) = 3.42 g BaCl2.

I hope this helps!
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