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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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michdem michdem
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11 years ago
what volume of 5.000 M sodium hydroxide is needed to prepare 100.0 mL of a 0.5000 M sodium hydroxide?

an explanation would be greatly appreciated as well!  thank you!  =]
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ilikepoopilikepoop
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11 years ago
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wrote...
#2
11 years ago
MV = MV
5M * V = 100ml * 0.5M
V = 100ml * 0.5M/5M = 10ml
wrote...
#3
11 years ago
10ml 5.000 M NaOH solution + 90ml H2O.

Explanation:
5.000 divided by 0.5000 = 10.
So you want it 1/10 of the strength it is now.
Thus, stick 1/10 of the final volume with 9/10 of the final volume.
You now have gone from a 5 M solution to a 0.5 M solution.
wrote...
#4
11 years ago
The question says that you need to prepare 100 ml of a 0.5 M solution of NaOH. 0.5 M solution means that 1 Litre
i.e. 1000 mL of solution has 0.5 moles of NaOH. So, by unitary method the number of moles of NaOH needed = (0.5 * 100)/1000
= 0.05 moles. NOW
You are given a 5 M solution, which means 1000 mL of the solution has 5 moles of NaOH. So, by unitary method, the volume of NaOH required to give
0.05 moles = (0.05 * 1000)/5
= 10 mL. Good Luck.....
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