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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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tony3320 tony3320
wrote...
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11 years ago
What volume of sodium hydroxide solution having a concentration of
0.1 mol dm-3 is needed to completely neutralise 50 cm3 of 0.75 mol dm-3
aqueous nitric acid?

HELP PLEASEEE
Thanks in advance, it is much appreciated.
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2 Replies
Replies
wrote...
#1
11 years ago
NaOH + HNO3 = NaNO3 + H2O

moles of HNO3 = .75 x 50 / 1000 = .0.0375  = moles of NaOH from the equation
volume of NaOH with these moles = number of moles / molarity
= .0.0375 / .1 =.375 / .1  liters or 375 mL
Answer accepted by topic starter
(catalina)(catalina)
wrote...
#2
Posts: 29
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11 years ago
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