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tosey tosey
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11 years ago
How many formula units of calcium hydroxide are needed to produce 0.0125 moles of aluminum hydroxide? Please show how you did it as well, thank you!
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#1
11 years ago
3Ca(OH)2 + 2Al Rightwards Arrow 2Al(OH)3 + 3Ca

According to the balanced reaction given above, the mole ratio between Al(OH)3 and Ca(OH)2 is 2:3 (or if you simplify, 1:1.5(or 3/2)

thus, n(Ca(OH)2) = n(Al(OH)3) x 1.5
                               = 0.0125 mol x 1.5
                                = 0.01875 mol

thus, 0.01875mol (=formula units) of Ca(OH)2 is needed.

hope this helps;-)
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