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gerrard gerrard
wrote...
Posts: 45
12 years ago
Two concentric, conducting spherical shell are charged as shown in the figure (+Q for the inner shell, +2Q for the outer shell). Using Gauss’s Law and the Charge Conservation principle, determine the charge on:
1)   Surface A (inner surface of the inner shell) [10 marks]
2)   Surface B (outer surface of the inner shell) [10 marks]
3)   Surface C (inner surface of the outer shell) [10 marks]
4)   Surface D (outer surface of the outer shell) [10 marks]
(Hint: what is the value of the electric field inside a conductor?)
If the outer radius of the outer shell is R = 15 cm, what is the electric field at a point P, 30 cm. from the outer edge? Write your answer as a function of Q. [10 marks]
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wrote...
12 years ago Edited: 12 years ago, mz24k
Never was good at algebra, so I wont confuse the situation,
Best of luck,
Mz
wrote...
Educator
12 years ago
1)   The charge on surface A (inner surface of the inner shell) is 0 (zero). This is because charges mainly remain on the surface of a shell and not on a shorter distance away from the radius.

2)   The charge on surface B (outer surface of the inner shell) is qenclosed = +Q.

3)   q= –Q where the electric field is zero E=O. In order to determine the charge at this point, one would have to draw a Gaussian circle within the conductor.

•   q enclosed + q outer = E = 0, from part 2) we know that q enclosed equals +Q so q outer equal –Q.

4)   The charge, q, on surface D (outer surface of the outer shell) is 2Q + Q = +3Q

The electric field at a point P is:
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