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4bio 4bio
wrote...
Posts: 47
Rep: 3 0
6 years ago
In the Caucasian population of North America, one out every 10 000 babies is born with a recessive condition known as phenylketonuria (PKU). This condition is controlled by a single pair of alleles. People who are homozygous recessive for the PKU gene completely lack the enzyme that is necessary to metabolize the amino acid phenylalanine into harmless by-products. The presence of the amino acid in a baby's diet can slow the development of the baby's brain. What percentage of the Caucasian population of North America would you expect to be heterozygous for the PKU allele?

I got 0.0198 or 2.0%
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wrote...
Educator
6 years ago Edited: 6 years ago, bio_man
That's correct

q^2 = 1/10,000
q = 1/100 = .01
p = 1 - q = .99
2pq = 2 * .99 * .01 = .0198
About 2% (answer)
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