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Micha Micha
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11 years ago
Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from n = 2 to n = 1.
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#1
11 years ago
En1 = 2.17 * 10 ^ -18 j
En2 = 5.425 * 10 ^ -19 j
En1-En2=1.6275 * 10 ^ -18 j
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11 years ago Edited: 8 years ago, bio_man
ΔE = hv where E = energy in joules, h = planck's constant = 6.626 x 10^-34 J*s; v = frequency in Hz (or s^-1)

ΔE = E2 - E1 = hv energy of photon going from n = 2 to n = 1
ΔE = - 13.6 eV[(1/2^2) - (1/1^2)]
1 eV = 1.6022 x 10^-19 J
ΔE = - 13.6 eV(1.6022 x 10^-19 J/eV)(0.25 - 1.00) = 1.63 x 10^-18 J or 10.2 eV
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